(x^2+2x)(x^2+2x+2)=1

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Solution for (x^2+2x)(x^2+2x+2)=1 equation: 


Simplifying
(x2 + 2x)(x2 + 2x + 2) = 1

Reorder the terms:
(2x + x2)(x2 + 2x + 2) = 1

Reorder the terms:
(2x + x2)(2 + 2x + x2) = 1

Multiply (2x + x2) * (2 + 2x + x2)
(2x * (2 + 2x + x2) + x2(2 + 2x + x2)) = 1
((2 * 2x + 2x * 2x + x2 * 2x) + x2(2 + 2x + x2)) = 1
((4x + 4x2 + 2x3) + x2(2 + 2x + x2)) = 1
(4x + 4x2 + 2x3 + (2 * x2 + 2x * x2 + x2 * x2)) = 1
(4x + 4x2 + 2x3 + (2x2 + 2x3 + x4)) = 1

Reorder the terms:
(4x + 4x2 + 2x2 + 2x3 + 2x3 + x4) = 1

Combine like terms: 4x2 + 2x2 = 6x2
(4x + 6x2 + 2x3 + 2x3 + x4) = 1

Combine like terms: 2x3 + 2x3 = 4x3
(4x + 6x2 + 4x3 + x4) = 1

Solving
4x + 6x2 + 4x3 + x4 = 1

Solving for variable 'x'.

Reorder the terms:
-1 + 4x + 6x2 + 4x3 + x4 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 4x + 6x2 + 4x3 + x4 = 0

The solution to this equation could not be determined.

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